Resolved: using C copy a 1D char array into 2D char array

//Here is what I tried for integers.<br />
        int main()<br />
    {<br />
        int arr[3][3];<br />
        int arr2[9]={1,2,3,4,5,6,7,8,9}; </p>
<p>        int i,j,k=0; </p>
<p>        for(i=0; i<3;i++){
            for(j=0; j<3;i++){
              arr[j][i] = arr2[i];
                //rintf("%d\n",arr2[i]);
            }
            
        }
    
     for(i=0; i<3; i++) { 
        for(j=0; j<3; j++) 
          printf("%2d  ", arr[j][i]); 
        printf("\n"); 
      } 
    
        return 0; 
    } 
[/code]

</p>



I changed my data to char and I tried to run the same code I got a segmentation error.
Here is what I have tried so far and it didnt work. <em><strong>error :Segmentation fault (core dumped)</strong></em><br> 


<p>[code] #include<stdio.h><br />
#include<string.h> </p>
<p>int main()<br />
{<br />
    char *d[3][3];  // Destination array </p>
<p>    char *s[9]={"orange","apple","table","chair","cable","TV", "124","HI"};   // Source 1 Day array</p>
<p>    int i,j,k=0; </p>
<p>    for(i=0; i<3;i++){
        for(j=0; j<3;i++){
            
          strcpy(d[j][i], s[i]);
           
        }
            }

 for(i=0; i<3; i++) { 
    for(j=0; j<3; j++) 
      printf("%s  ", d[j][i]); 
    printf("\n"); 
  } 

    return 0; 
} 
[/code]

</p>



I have made some adjustment and now it print some weird strings<br> 


<p>[code]#include<stdio.h><br />
#include<string.h> </p>
<p>int main() { </p>
<p>    char d[3][3] ={0};  // Destination array </p>
<p>    char s[9][8]={"orange","apple","table","chair","cable","TV", "124","HI"};   // Source 1 Day array</p>
<p>    int i,j,k=0; </p>
<p>    for(i=0; i<3;i++){
        for(j=0; j<3;j++){

            d[j][i] = *s[i];
           
        }
            }
    
    for(i=0; i<3; i++) { 
        for(j=0; j<3; j++) 
            printf("%s  ", &d[j][i]); 
            printf("\n"); 
    } 

    return 0; 
} 
[/code]

</p>



<a href="https://i.stack.imgur.com/uJ791.png" rel="nofollow noreferrer">enter image description here</a><br> 



<h2>Answer:</h2>



This for loop<br> 


<p>[code]    for(i=0; i<3;i++){
        for(j=0; j<3;i++){
          arr[j][i] = arr2[i];
            //rintf("%d\n",arr2[i]);
        }
        
    }
[/code]

</p>



is incorrect. In the inner loop there are used the same elements <code>arr2[i]</code> where <code>i</code> is changed from <code>0</code> to <code>2</code> inclusively.<br> 



You need to write<br> 


<p>[code]    for(i=0; i<3;i++){
        for(j=0; j<3;i++){
          arr[j][i] = arr2[ 3 * i + j];
        }
    }
[/code]

</p>



Another way to write loops is the following<br> 


<p>[code]    for ( i = 0; i < 9; i++ )
    {
        arr[i / 3][i % 3] = arr2[i];
    }
[/code]

</p>



As for arrays of pointers of the type char * then the nested loops will look similarly<br> 


<p>[code]for(i=0; i<3;i++){
    for(j=0; j<3;i++){
        
      d[i][j] = s[ 3 * i + j];
       
    }
}
[/code]

</p>



provided that the array s is declared like<br> 


<p>[code]char * s[9]={"orange","apple","table","chair","cable","TV", "124","HI"};