Resolved: String replace digits 0123456789 with X in Swift iOS

Question:

Need to replace phone number list with X and format should stay the same.
For example:

Input-> 201-555-0123 -> Expected Output: XXX-XXX-XXXX
Input-> 612 34 56 78 -> Expected Output: XXX XX XX XX
Input-> 9 11 2345-6789 -> Expected Output: X XX XXXX-XXXX
Input-> 622-1234 -> Expected Output: XXX-XXXX

Can anyone suggest proper way of finding digits 0 to 9 in the string and replace with X.
Tried as below it doesn’t finds number and returns same.

func getMaskedNumber(formattedPhoneNumber: String) -> String {
        let maskedNumber = formattedPhoneNumber.replacingOccurrences(of: "[0-9]", with: "X")
        return maskedNumber
}

 numberToDisplay = getMaskedNumber(formattedPhoneNumber: "201-555-0123") // Expected O/P as XXX-XXX-XXXX

Answer:

You can use regex. Try this:

func getMaskedNumber(formattedPhoneNumber: String) -> String {
    return formattedPhoneNumber.replacingOccurrences(of: "[0-9]", with: "X", options: .regularExpression, range: nil)
}

If you have better answer, please add a comment about this, thank you!

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