Resolved: Recursive function that takes a string as argument and determines if the string has more vowels than consonants

def recursiveVowels(str):
    vowels = ['a','e','i','o','u']
    vowels_count =0
    if len(str) == 0:
        return vowels_count
    elif str[0] in vowels:
        vowels_count += 1

    total_vowels =   vowels_count + recursiveVowels(str[1:])
    # check if no of vowels are more than half the length of string
    return total_vowels > (len(str)/2)

print(recursiveVowels("Targeiout"))

def recursiveVowels(str):<br />
    vowels = ['a','e','i','o','u']<br />
    vowels_count =0<br />
    if len(str) == 0:<br />
        return vowels_count<br />
    elif str[0] in vowels:<br />
        vowels_count += 1</p>
<p>    total_vowels =   vowels_count + recursiveVowels(str[1:])<br />
    return total_vowels</p>
<p># made a seperate function just to check if vowels are more than consonants<br />
def isVowelsMore(str):<br />
    vowels = recursiveVowels(str)<br />
    return (len(str)/2) < vowels
[/code]

</p>



this will return <code>True</code>:<br> 


<p>[code]print(isVowelsMore("Targeiout"))

total_vowels =   vowels_count + recursiveVowels(str[1:])

 total_vowels =   vowels_count + False

total_vowels =   vowels_count + True