Resolved: Multiply by a different number of columns with iloc in Pandas

df = pd.DataFrame({'date' : ['2020-6','2020-07','2020-8'], 'd3_real':[1.2,1.3,0.8], 'd7_real' : [1.5,1.8,1.2], 'd14_real':[1.9,2.1,1.5],'d30_real' : [2.1, 2.2, 1.8],
                   'd7_mul':[1.12,1.1,1.15],'d14_mul':[1.08, 1.1, 1.14],'d30_mul':[1.23,1.25,1.12]})

df['d30_from_d3'] = df.iloc[:,1] * df.iloc[:,5] * df.iloc[:,6] * df.iloc[:,7]
df['d30_from_d7'] = df.iloc[:,2] * df.iloc[:,6] * df.iloc[:,7]
df['d30_from_d14'] = df.iloc[:,3] * df.iloc[:,7]

pos_reals = [1,2,3]
pos_mul = [5,6,7]
clases = ['d3', 'd7','d14']

for target in pos_reals:
  for clase in pos_mul:
    df[f'f{clases}_hm_p_d30']  = df.iloc[:,target]

bbb = [[1, 5, 6, 7], [2, 6, 7], [3, 7]]
ddd = ['d30_from_d3', 'd30_from_d7', 'd30_from_d14']
for i in range(0, len(ddd)):
    df[ddd[i]] = df.iloc[:, bbb[i][0]]
    for x in range(1, len(bbb[i])):
        df[ddd[i]] = df[ddd[i]] * df.iloc[:, bbb[i][x]]

      date  d3_real  d7_real  d14_real  d30_real  d7_mul  d14_mul  d30_mul  \
0   2020-6      1.2      1.5       1.9       2.1    1.12     1.08     1.23   
1  2020-07      1.3      1.8       2.1       2.2    1.10     1.10     1.25   
2   2020-8      0.8      1.2       1.5       1.8    1.15     1.14     1.12   

   d30_from_d3  d30_from_d7  d30_from_d14  
0     1.785370      1.99260         2.337  
1     1.966250      2.47500         2.625  
2     1.174656      1.53216         1.680