Resolved: How can I add 0's to a string based on string length difference compared to target length?

Question:

I need to make sure all cells in each column have that column’s target length. When the target length is larger than the actual length of the string value in the given cell, x amount of 0s must be added in front in order to make the string’s length be equal to the target.
So far I have this code:

Dim row_counter1 As Long
Dim char1 As Integer
Dim char_dif1 As Integer
Dim char_targ1 As Integer
    char_targ1 = 2
For row_counter1 = 2 To last_row_index(output, 1)
    char1 = Len(output.Cells(row_counter1, 1))
    char_dif1 = char_targ1 - char1
    Debug.Print char_dif1
Next row_counter1

last_row_index is a simple UDF using the End.xlUp method to find last continuous row index. The loop works well, giving me the difference in Integer format.
Taking that integer and turning it into 0s that go in front of the cell.value is the issue I am having trouble solving. I have seen solutions to similar problems for Python, but I am very new to coding and I am having trouble understanding the process.

Answer:

in the cell like this, e.g. for 10 digits of length:

=RIGHT(“0000000000000”&A1,10)

If you have better answer, please add a comment about this, thank you!

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