Resolved: Error when accessing incorrect url in python requests 0 By Isaac Tonny on 16/06/2022 Issue Share Facebook Twitter LinkedIn Question: import requests url = "http://sdfsdfasdfsfsdf.com" res = requests.get(url) if res == 200: print("ok") else: print("wrong") As shown in the code above, I want to print out “wrong” when I access an unusual url. However, the following error occurs. Traceback (most recent call last): File "/Library/Frameworks/Python.framework/Versions/3.9/lib/python3.9/site-packages/urllib3/connection.py", line 174, in _new_conn conn = connection.create_connection( File "/Library/Frameworks/Python.framework/Versions/3.9/lib/python3.9/site-packages/urllib3/util/connection.py", line 72, in create_connection for res in socket.getaddrinfo(host, port, family, socket.SOCK_STREAM): File "/Library/Frameworks/Python.framework/Versions/3.9/lib/python3.9/socket.py", line 954, in getaddrinfo for res in _socket.getaddrinfo(host, port, family, type, proto, flags): socket.gaierror: [Errno 8] nodename nor servname provided, or not known Do you know the solution to this? Answer: It’s likely because the hostname can’t be resolved Alternative could use try except block here import requests url = "http://sdfsdfasdfsfsdf.com" try: res = requests.get(url) if res.status_code == 200: print("ok") else: print('wrong') except: print('wrong') If you have better answer, please add a comment about this, thank you! python python-requests