Resolved: Create Table/Dataframe with only Max values from Columns and corresponding Values in Row

Question:

I have a (for me) difficult idea for my dataframe

# A tibble: 6 x 28
  Full.Name `1_2019` `1_2020` `10_2019` `10_2020` `11_2019` `11_2020` `12_2019` `12_2020` `2_2019` `2_2020`
  <chr>        <dbl>    <dbl>     <dbl>     <dbl>     <dbl>     <dbl>     <dbl>     <dbl>    <dbl>    <dbl>
1 Adena T.~  -0.383   -0.216    -0.330     -0.602   -0.426     -0.266   -0.361   -0.253   -0.290     -0.401
2 Albert B~  -1.06    -0.195    -0.321     -0.535   -0.516     -0.308   -0.475   -0.328   -1.01      -0.443
3 Christop~  -0.0842  -0.217    -0.259      0.251   -0.340     -0.163   -0.275   -0.00184 -0.164     -0.339
4 Colin M.~  -1.06    -0.0936   -0.166     -0.570   -0.0989    -0.311   -0.0126  -0.386   -1.01       0.120
5 Derek J.~  -0.0993  -0.153     0.192     -0.110   -0.0643    -0.145    0.0424  -0.169   -0.00159    1.20 
6 Eileen P~   0.580   -0.0270    0.0469     0.759    0.302      0.320    0.402    0.0158  -0.440      0.992
# ... with 17 more variables: `3_2019` <dbl>, `3_2020` <dbl>, `4_2019` <dbl>, `4_2020` <dbl>,
#   `5_2019` <dbl>, `5_2020` <dbl>, `6_2019` <dbl>, `6_2020` <dbl>, `7_2019` <dbl>, `7_2020` <dbl>,
#   `8_2019` <dbl>, `8_2020` <dbl>, `9_2019` <dbl>, `9_2020` <dbl>, Entity <chr>, Ticker.Symbol <chr>,
#   Ra <dbl>

I want to create a table, which gives out the max for each time-column [2:25], but I don’t only want to include the value for the max, but I want to show the Full.Name value for the corresponding max value. The output should look like this:

Is that even possible within the R envorimnent? This greatly exeeds my knowledge of R and is a real specific problem.
An alternative would be to count how many times a Full.Name has a max value for the mentioned columns. The output here should look like this:

Depending on what is better/easier to do – both solutions would satisfy my needs, but the first one is preffered, if possible.
Any help is appreciated. Thanks!
This is the dput() output:
structure(list(Full.Name = c(“Adena T. Friedman”, “Albert Bourla, D.V.M., DVM, Ph.D.”, “Christopher A. Caldwell”, “Colin M. Angle”, “Derek J. Leathers”, “Eileen P. Drake”), 1_2019 = c(-0.383055707155795, -1.05904949909804, -0.0842258334645898, -1.05904949909804, -0.0992767433029089, 0.579723329852852), 1_2020 = c(-0.216468956246416, -0.195482903945435, -0.217062894420478, -0.0935901304701391, -0.153203397403474, -0.0269547804807655), 10_2019 = c(-0.330254033944817, -0.320924627792365, -0.259035596196796, -0.165521585779242, 0.191622624792709, 0.0468503831648096 ), 10_2020 = c(-0.602152189359244, -0.535418283344491, 0.250595906332612, -0.569859279903607, -0.110044980526754, 0.758921953633378), 11_2019 = c(-0.426305396694651, -0.515785519108897, -0.339519299471372, -0.0989134193907651, -0.0643284748215571, 0.302353842370004), 11_2020 = c(-0.266358518183409, -0.307946402525424, -0.163463742373844, -0.311354999046801, -0.145418823259319, 0.319519922634799), 12_2019 = c(-0.360807066616068, -0.475346190769451, -0.275106046438998, -0.0126324599828461, 0.0423954161102351, 0.402048846748391), 12_2020 = c(-0.252841249834664, -0.327543659166096, -0.0018365708720592, -0.385790707531874, -0.168610938237114, 0.0157769121978877), 2_2019 = c(-0.289816736567697, -1.01038671729134, -0.163531276028501, -1.01038671729134, -0.00158874427823888, -0.439935482551789), 2_2020 = c(-0.400669734118479, -0.443383016682402, -0.33938545913546, 0.119970547944465, 1.19680703377221, 0.992446784767351 ), 3_2019 = c(-0.282321826547816, -0.663729475667504, -0.143945270922075, -0.663729475667504, -0.21135343810465, -0.0113472595074246), 3_2020 = c(0.210034583053767, -0.119257597883072, 0.0604507532275685, -0.0156610190075263, 0.244957142838736, 0.931989699546531 ), 4_2019 = c(-0.0943196744817198, -1.40545668795108, -0.242173427911943, -1.40545668795108, -0.308396700646459, 0.328421577075603), 4_2020 = c(-0.603468919897277, -0.46742517184902, 0.458562501566214, -0.415513741672711, -0.0675211576243626, 1.33393253995762 ), 5_2019 = c(-0.129921217468993, -1.43714052178394, -0.141050793589322, -1.43714052178394, 0.0899785102237378, 0.282749974677489), 5_2020 = c(-0.108187683872424, -0.487161950868388, -0.383969978742953, -0.452015143848601, -0.128294552876879, 1.31749515416976), 6_2019 = c(-0.148193355904154, -1.28016746608286, -0.44221260530122, -0.258433114852674, -0.218530887721297, 0.116423968553205 ), 6_2020 = c(-0.746183120363155, -0.551046867139016, 0.437251904764289, -0.311162387486119, 0.384217485429955, 1.81560563991272), 7_2019 = c(-0.345861092486428, -0.42039491332283, -0.177019171816214, -0.0648826509182595, -0.28646337065065, -0.0977527167183953 ), 7_2020 = c(-0.288166498436476, -0.288339408366061, -0.206961079106134, -0.177119025931579, -0.197207687539335, 0.144917519117581 ), 8_2019 = c(-0.364262512827361, -0.245902656766371, -0.20578067166095, 0.0553125457840526, -0.328962204879346, -0.092965764103294 ), 8_2020 = c(-0.395704012557836, -0.413354561981113, -0.254541944628269, -0.162952100829554, -0.0979980789518939, 0.688768946608496 ), 9_2019 = c(-1.34762262072134, -0.0330072964653664, -0.436255871711975, -0.0372309601577549, -0.188601863828996, 0.208072109502548 ), 9_2020 = c(-0.464351916504254, -0.240626492556919, -0.116659195276997, -0.616441955671251, -0.279371793278997, 0.735245489136106 ), Entity = c(“NASDAQ INC”, “PFIZER INC”, “CONCENTRIX CORP -SPN”, “IROBOT CORP”, “WERNER ENTERPRISES INC”, “AEROJET ROCKETDYNE HOLDINGS” ), Ticker.Symbol = c(“NDAQ”, “PFE”, “CNXC”, “IRBT”, “WERN”, “AJRD”), Ra = c(0.559536371978057, 0.0400867733394902, 0.241250053137799, 0.376713156282756, 0.458131711187552, 0.636418544760744)), row.names = c(NA, -6L), class = c(“tbl_df”, “tbl”, “data.frame”))

Answer:

You could reshape your data to long format (with dplyr::pivot_longer, for example) and then filter only the rows with the maximum value, among those grouped_by month:

library(tidyr)
library(dplyr)

dat |> 
  pivot_longer(-Full.Name, names_to = "month") |> 
  group_by(month) |> 
  filter(value == max(value))

Output

#> # A tibble: 10 × 3
#> # Groups:   month [10]
#>    Full.Name month        value
#>    <chr>     <chr>        <dbl>
#>  1 DerekJ.~  `10_2019`  0.192  
#>  2 DerekJ.~  `2_2019`  -0.00159
#>  3 DerekJ.~  `2_2020`   1.2    
#>  4 EileenP~  `1_2019`   0.58   
#>  5 EileenP~  `1_2020`  -0.027  
#>  6 EileenP~  `10_2020`  0.759  
#>  7 EileenP~  `11_2019`  0.302  
#>  8 EileenP~  `11_2020`  0.32   
#>  9 EileenP~  `12_2019`  0.402  
#> 10 EileenP~  `12_2020`  0.0158

^{Created on 2022-06-16 by the reprex package (v2.0.1)}

If you have better answer, please add a comment about this, thank you!

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