Resolved: Bash: For Loop & save each output as a new column in a csv

Question:

I have a folder with a mixture of files types (.bam, .bam.bai, and .log). I created a for loop to perform two commands on each of the .bam files. My current code direct the output of each command into a separate csv files, because I could not figure out how to direct the outputs to separate columns.
TYIA!
Question 1
I want to export the output from the commands into the same csv. How can I alter my code so that the output from my first command is saved as the first column of a csv, and the output from my second command is saved as the second column of the same csv.
Question 2
What is the name of the syntax used to select files in a for loop? For instance, the * in *.bam represents a wildcard. Is this regex? I had a tough time trying to alter this so that only *.bam files were selected for the for loop (and .bam.bai were excluded). I ended up with *[.bam] by guessing and empirically testing my outputs. Are there any websites that do a good job of explaining this syntax and provide lots of examples (coder level: newbie)
Current Code
Current Outputs (truncated)
Desired Output

Answer:

Something like
Print one line for each file, and move the output redirection outside of the loop for efficiency.

If you have better answer, please add a comment about this, thank you!